>> codigo_oneinamillion=PideCodigo(codigo)
>> muestracodigo_fig(codigo_oneinamillion)
>> codigo_oneinamillion=rmfield(codigo_oneinamillion,’aa2codon’)
>> save codigo_oneinamillion codigo_oneinamillion
Now, look for the nearest ‘optimal’ code:
>> [codigo_final,errormin,errormedio]=acercacodigos(codigo,codigo_oneinamillion);
>> errormin
errormin =
0.7031
>> errormin*64
ans =
45
A bit nearer than yesterday.
>> sum(errormedio(:)==min(errormedio(:)))
ans =
4
And there are 4 permutations that match equally well (this also happened yesterday).